Hardy Weinburg Questions

Hi everyone

I just wanted to give you some help on the Hardy Weinburg homework problems.

1. In a population of 100 individuals 49% are of the NN blood type. What
percentage is expected to be MN assuming Hardy-Weinberg equilibrium?
A. 9%
B. 21%
C. 42%
D. 51%
E. insufficient information to answer question

OK, this one was a bit difficult because it is an example of codominance.

In this cause NN represents q squared.

So if q squared = .49, then if you take the square root of each side, q = .7

Remember that p + q = 1

So if q = .7 then p = .3

Now to figure out the heterozygous condition, you need to multiply using 2pq

So, 2(.7)(.3) = .42 or 42%